a^2+30a-540=0

Solution for a^2+30a-540=0 equation:

a^2+30a-540=0

a = 1; b = 30; c = -540;
Δ = b2-4ac
Δ = 302-4·1·(-540)
Δ = 3060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3060}=\sqrt{36*85}=\sqrt{36}*\sqrt{85}=6\sqrt{85}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{85}}{2*1}=\frac{-30-6\sqrt{85}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{85}}{2*1}=\frac{-30+6\sqrt{85}}{2}
$